Math, asked by shantilalsonawane4, 10 months ago

2) The roots of kx² + 2kx +6=0 are real and equal, find k.
b) 4 (c) 2 d) 6
a) o​

Answers

Answered by Himanshu249403Z
0

Given equation= Kx^+2Kx+6

And B^-4AC=0

SO, a=k, b=2k and c=6

So, (2k)^-4(k)(6)=0

4k^-24k=0

4k=24

K=6. Answer

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