Question

2. The runs scored in a cricket match by 11 players is as follows:
6, 15, 120, 50, 100, 80, 10, 15, 8, 10, 15
Find the mean, mode and median of this data. Are the three same?​

Answer 1

Answer:

$\bold{Mean = \frac{sum \: of \: all \: terms}{number \: of \: terms}} \\ = \frac{6 + 15 + 120 + 50 + 100 + 80 + 10 + 15 + 8 + 10 + 15}{11} \\ = \frac{429}{11} = 39 \\ \fbox {Mean = 39 } \\ \bold {mode = number \: that \: occurs \: most \: times} \\ \fbox{mode = 15} \\ \bold{median \: =( { \frac{n + 1}{2} })^{th}} \: because \: n \: is \: odd. \\ n = \frac{11 + 1}{2} \\ n = \frac{12}{2} = 6 \\ \fbox{median \: = 6th \: term } \\ putting \: all \: numbers \: in \: ascending \: order \\ = 6,8,10,10,15,\bold{15},15,50,80,100,120\\ \fbox{median \: = 15}$

No,the three are not same .

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Answer 2

your answer is in attachment