2. The scores of Sachin in consecutive five innings are 80, 90, 100, 100 and m
respectively. The average of the five innings is 100, then comparing with his first
innings score, how much more has he scored in his last innings?
(1) 50 (2) 20 (3) 130 (4) 10
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answer :
100= 80+90+100+100 divided by 5
100x5=370+m
500-370=m
therefore,m=130
therefore, m-first innings
=130-80
=50
therefore, the right answer is 50
.'. Hence prove
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