Question

2. The side of a square exceeds the side of
another square by 5 cm. The difference
of their areas is 325 sq. cm. Find the sides of
each square​

Answer 1

Step-by-step explanation:

Let the two squares be s1 and s2

Let the side of s1 be x cm

side of s2=(x+5)cm

area of square= side*side

area of s1=x²sq.cm

area of s2=(x+5)²sq.cm

=x²+10x+25

x²+10x+25-x²=325

x²-x²+10x+25=325

0+10x=325-25

10x=300

x=300/10

x=30cm

side of s1=30cm

side of s2=35cm