Question

2
The side of a square is 5 cm and the
area of a rectangle is twice the area
of this souare. So what is the area of
the rectangle?
1 25 soom
2 100 socm
3 50 soom
4 125 som
19:41​

Answer 1

Step-by-step explanation:

hope this answer is helpful to you

Answer 2

Answer:

Option 3

Step-by-step explanation:

Given :-

The side of a square is 5 cm and the

area of a rectangle is twice the area

of this souare.

To find:-

What is the area of the rectangle?

Solution:-

The side of a square = 5 cm

We know that

Area of a square whose side is 'a' units is 'a^2 ' sq.units

We have , a = 5 cm

Area of the given square

= 5^2 sq.cm

=5×5 sq.cm

= 25 sq.cm

Given that

area of a rectangle is twice the area of the square

=> Area of a rectangle = 2× Area of the square

=> 2×25 sq.cm

=> 50 sq.cm

Therefore, Area = 50 sq.cm

Answer:-

Area of the rectangle for the given problem is

50 sq.cm

Used formulae:-

1. Area of a square = side^2 = a^2 sq.units

Where , a = Side of the square.

• Area of a rectangle =lb sq.units

Where, l = length of the rectangle

and b = breadth of the rectangle