Math, asked by SkAbdusSami, 1 year ago

2
The smallest number should 7803 be multiplied with so that the product becom
a perfect cube is
a) 3
b) 17
c) 9
d) 289


SkAbdusSami: Make prime factorization to 7803 then result is 3*3*3*17*17,so 17 becomes the answer

Answers

Answered by waqarsd
1

\large{ \bold{7803 = 3 \times 2601}} \\  \\ \large{ \bold{7803 = 3 \times 3 \times 867}} \\  \\ \large{ \bold{7803 = 3 \times 3 \times 3 \times 289}} \\  \\ \large{ \bold{7803 = 3 \times 3 \times 3 \times 17 \times 17}} \\  \\ \large{ \bold{7803 =  {3}^{3} \times  {17}^{2}  }} \\  \\ \large{ \bold{7803 \times 17 =  {3}^{3}  \times  {17}^{3} }} \\  \\ \large{ \bold{ \sqrt[3]{7803  \times  17} =  \sqrt[3]{ {3}^{3} \times  {17}^{3}  } } } \\  \\ \large{ \bold{ \sqrt[3]{7803 \times 17}  = 17 \times 3 = 51}} \\  \\ \large{ \bold{therefore \: the \: multiplied \: number \: is \: 17}}

\large{ \bold{correct \: option \: is \: (b)}} \\  \\ \large{ \bold{hope \: it \: helps}}

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