Question

2. The solubility product for BaSO4 at 18-25°C is:
a) 1.0 x 10-40 mole dm
b) 8.7 x 10-36 mole dm
C 1.8 x 1021 mole dm
d) 8.4 x 102 mole dm
e) 3.5 x 10-52 mole' dm. plz give solution​

Answer 1

be the molar solubility of barium sulphate.

For barium sulphate;

K

sp

=[Ba

2+

][SO

4

2−

]

=S×S=S

2

Molar solubility of barium sulphate, S=

Ksp

=

1.5×10

−10

=1.2×10

−5

M