Question

2. The solution set of cot 0 =-
$\sqrt{3}$
3, cosece = 2 is​

Answer 1

Find principal and general solution of the equation, cotx=−3

cotx=− 3

We know, cot 6π = 3

Therefore, cot(π− 6π )=−cot 6π =− 3 and cot(2π− 6π )=−cot 6π =− 3cot 6,5π =− 3 and cot 6,11π=−3

Therefore, the principal solutions are x=

6,5π and 6,11π

Now, cotx=cot 6,5πtanx=tan 6,5πx=nπ+ 6,5π

Therefore, the general solution is x=nπ+ 6,5πn∈Z.

Step-by-step explanation:

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