2. The speed of the boat in still water is 5 times that of the current, it takes 1.1 hours to row to point
B from point A downstream. The distance between point A and point Bis 13.2 km. How much
distance (in km) will it cover in 312 minutes upstream?
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Let the speed of the current be x kmph
Then speed of the boat in still water = 5x
∴Downstream speed = (5x+x)=6xkmphUpstream speed = (5x−x)=4xkmphNow, 13.2kmA¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯BAccording to question,1.1×6x=13.2⇒6.6x=13.2⇒x=13.26.6∴x=2kmph∴Upstream speed = 4x=4×2=8kmph∴312 minutes=515hours=265hours∴Required distance travelled upstream = Speed ×Time = 8×265=41.6km
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