2. The sum of a two digit number and the
number obtained by interchanging the digits
is 99. If the digit at tens place exceeds thedigit at units place by 3, find the number.
3. Two numbers are in the ratio 3:4. If 5 is
added to each number, their ratio becomes
7:9. Find those numbers.
4. The sum of the numerator and the denominator
of a fraction is 9. If 3 is added to each of
the numerator and the denominator, it becomes
1/2. Find the fraction.
Answers
.............................................
Answer:
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+x
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+y
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,(10y+x)+(10x+y)=99
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,(10y+x)+(10x+y)=99=11x+11y=99
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,(10y+x)+(10x+y)=99=11x+11y=99=x+y=9 ......1
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,(10y+x)+(10x+y)=99=11x+11y=99=x+y=9 ......1And,x−y=±3 ......2 (given)
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,(10y+x)+(10x+y)=99=11x+11y=99=x+y=9 ......1And,x−y=±3 ......2 (given)On solving equation 1 and 2 ,we get
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,(10y+x)+(10x+y)=99=11x+11y=99=x+y=9 ......1And,x−y=±3 ......2 (given)On solving equation 1 and 2 ,we getx=6,y=3 or x=3,y=6
Answer:2) Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,(10y+x)+(10x+y)=99=11x+11y=99=x+y=9 ......1And,x−y=±3 ......2 (given)On solving equation 1 and 2 ,we getx=6,y=3 or x=3,y=6Hence the required number is either63 or 36.