2. The sum of the angles of a polygon is 8100°.
a. How many sides does it have?
b. What is the sum of the outer angles of any polygon?
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Use the formula sum of the interior angles of a polygon is (n-2)180 degrees, where n is the number of sides of the polygon,
In this example,
(n-2)180= 8100
Therefore,
180n-360=8100
180n=8460
Therefore, n= 8460/180=846/18=47
Therefore, the number of sides of the polygon is 47
b) The sum of the outer(exterior) angles of any polygon is equal to 360 degrees
In this example,
(n-2)180= 8100
Therefore,
180n-360=8100
180n=8460
Therefore, n= 8460/180=846/18=47
Therefore, the number of sides of the polygon is 47
b) The sum of the outer(exterior) angles of any polygon is equal to 360 degrees
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