Question

2. The sum of the digits of a 2-digit number is 17. On reversing the digits, the number formed is 9 mon
than the original number. Find the original number ​

Answer 1

Answer:

let the digit in tens place be x and units place be y

: . the original number=10x+y

on reversing the digits, new number=10y+x

according to the 1st condition

x+y=17.........©

according to the 2nd condition

10y+x=10x+y+9

10x-x+y-10y=-9

9x-9y=-9

dividing throughout by 9

x-y=-1......®

©+®

x+y=17

x-y-1

______

2x=18

: .x=9

substitute x=9 in ©

9+y=17

: .y=17-9

= 8

original number=10x+y

=10(9)+8

98

Answer 2

Step-by-step explanation:

Let one's digit be x

Let ten's digit be 10y

A/Q

x+10y= 17---i

By reversing the digit we get

10x + y = 9+17(Because it is given more than original one)

So,

10x + y = 26--ii

Solving this get the answers