2. The sum of the digits of a two digit number is 12. If the new number formed by reversing the
digits is greater than the original number by 54, find the original number.
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LET THE ONE'S DIGIT BE X
TENS DIGIT BE Y
ORIGINAL NO.->. 10Y+X
REVERSING NUMBER. -> 10X+Y
A.T.Q
X+Y=12. 1 equation
10X+Y=10Y+X+54
10X+Y-10Y-X=54
9X-9Y=54. (DIVIDING BY 9)
X-Y=6. 2 equation
from 1 and 2 equation
X+Y=12
X-Y=6
________
2X. =18
X=18/2
X=9
PUTTING X=9 IN 1 EQUATION
X+Y=12
9+Y=12
Y=12-9
Y=3
THEREFORE X=9 ,Y=3
THANK YOU
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