Question

2. The sum of the digits of a two-digit number is 12. If the digits are reversed, the new number formed is 36 less than the original number. Find the original number.

Answer 1

Answer:

Let the two digit number be 10x+y

Sum of digit : x + y=12 __(i)

A.T.Q : 2(10x+y)−(10y+x)=12

     ⇒20x+2y−10y−x=12

    ⇒19x−8y=12

    ⇒19x−8y−12=0 __(ii)

Put eq. ( I ) in eq. (ii)

   ⇒19(12−y)−8y−12=0

   ⇒228−19y−8y−12=0

   ⇒27y=216

   ⇒y=8  

x + y=12

x=12−8

x=4

Number : 48

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