2) The sum of the natural numbers from 1 to n is 36. Find the value
of n.
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sn=n/2{2a+(n-1)d}
now-
natural no.s start from 1
a=1;d=1;sn=36;n=?
36=n/2{2×1+(n-1)1}
36×2=n{2+n-1}
72=n{n+1}
72=n^2+n
n^2+n-72=0
By quadratic formula
a=1;b=1;c=(-72)
d=b^2-4ac
d=1+288
d=289
x=-b+*√d÷2a;-b-√d÷2a
x=-1+17/2;1-17/2
x=18/2;-16/2
x=9,-8(neglecting)
so,x=9
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