(2) The sum of third and seventh term of an A. P. is 6 and their product is
8. Find the first term and the common difference of the A. P.
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Answered by
2
let the first term of the AP be a
and common difference of the AP be d
since it is given that the sum of the 3rd term and 7th term of the AP is 6
so the system of equation can be written as
a+ 2d+ a+ 6d=6
2a + 8d = 6
(dividing whole equation by 2)
a+4d=3 --------(1)
secondly there is a given that product of third term and seventh term is 8
so system of equation can be written as
(a+2d)(a+6d)=8
a^2+6ad+2ad+12d^2=8
a^2+8ad+12d^2=8---------(2)
from first and second equation
we can find the value of a and d
and common difference of the AP be d
since it is given that the sum of the 3rd term and 7th term of the AP is 6
so the system of equation can be written as
a+ 2d+ a+ 6d=6
2a + 8d = 6
(dividing whole equation by 2)
a+4d=3 --------(1)
secondly there is a given that product of third term and seventh term is 8
so system of equation can be written as
(a+2d)(a+6d)=8
a^2+6ad+2ad+12d^2=8
a^2+8ad+12d^2=8---------(2)
from first and second equation
we can find the value of a and d
Artisticsk:
it will be in square
Answered by
1
a+2d + a + 6d = 6
2 a + 8d = 6
a + 4d = 3 -----1
(a+2d)(a+6d) = 8
u can solve now ..
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