Question

2. The sum of two number is 100. If one exceeds the other by 10 ,find the numbers.
Ans:​

Answer 1

$\huge{\underline{\mathfrak{Answer:-}}}$

Let the first number be x.

Then another number will be x+16.

According to question, sum of the numbers is 100.

⇒x+x+16=100

⇒2x=84

⇒x=42

First number =42

Other number, x+16=42+16=58

find ur answer in this way this is not correct answer

Answer 2

Answer:

Given :-

• The sum of two numbers is 100. If exceeds the other by 10.

To Find :-

• What is the number.

Solution :-

Let, the first number be x

And, the second number will be x + 10

According to the question,

↦ $\sf x + x + 10 =\: 100$

↦ $\sf 2x + 10 =\: 100$

↦ $\sf 2x = 100 - 10$

↦ $\sf 2x =\: 90$

↦ $\sf x =\: \dfrac{\cancel{90}}{\cancel{2}}$

➠ $\sf\bold{\red{x =\: 45}}$

Hence, the required numbers are,

➤ First number = x = 45

➤ Second number = x + 10 = 45 + 10 = 55

$\therefore$ The numbers are 45 and 55.

VERIFICATION :-

⇒ $\sf x + x + 10 =\: 100$

By putting x = 45 we get,

⇒ $\sf 45 + 45 + 10 =\: 100$

⇒ $\sf 100 =\: 100$

➦ LHS = RHS

Hence, Verified ✓