Question

2. The tip of a pin has an area of 0.00001 m². Calculate
pressure exerted by it if force applied is 10 N.​

Answer 1

GIVEN :–

• Area = 0.00001 m²

• Applied force = 10 N

TO FIND :–

• Pressure = ?

SOLUTION :–

• We know that –

$\\ \implies \large \red{ \boxed{\bf P= \dfrac{F}{A}}}$

• Now put the values –

$\\ \implies\bf P= \dfrac{10}{0.00001}$

$\\ \implies\bf P= \dfrac{10}{1 \times {10}^{ - 5} }$

$\\ \implies\bf P= \dfrac{10^{1} \times {10}^{5}}{1}$

$\\ \implies\bf P= \dfrac{10^{(1 + 5)}}{1}$

$\\ \implies\bf P=10^{(1 + 5)}$

$\\ \implies \large \red{ \boxed{\bf P=10^{6} \: \: \:N/m^2}}$

⇨ Hence , Pressure exerted by force on tip of a pin is 10⁶ N/m².

Answer 2

✴ Given :

• Area = 0.00001 m²
• Applied force = 10 N

✴ To find :

• Calculate the pressure ?

✴ Formula :

$\bigstar \sf \: We \: know \: that, \boxed{\boxed{ \pink{ \bf \: p =\frac{F}{A}}}}$

✴ Let's Do that :

$\: \: \: \: \: \: \red\maltese \sf \: \: P = \sf\frac{10}{0.00001}$

$\: \: \: \: \: \: \: \: \: \: \: \: \red\maltese \sf \: P = \frac{10}{ 1\times 10 {}^{ - 5} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \red \maltese \: \sf P = \frac{10 {}^{1} \times 10 {}^{5} }{1}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \red \maltese \sf \: P = \frac{10 {}^{(1 + 5)} }{1}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\red\maltese \sf \: P = 10 {}^{(1 + 5)}}$

$\: \: \: \: \: \: \: \: \: \bigstar \: \purple{\boxed{\boxed{\sf \: P = 10 {}^{6} n/m {}^{2}}}}$