2. The triangular side walls of a flyover have been used for advertisements. The si
the walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advertisements yield
eaming of Rs 5000 per mº per year. A company hired one of its walls for 3 months ;
much rent did it pay?
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Answer:
Refer figure,
In △ABC
a=122m,b=22m,c=120m
s= a+b+c
= 122+22+120
=132m
ar△ABC=√ s(s−a)(s−b)(s−c)
=√132(132−122)(132−23)(132−120)
= √132×10×110×12
= √
132×10×11×10×12
=√(132)² × (10)²
=132 × 10
=1320 m²
Rent of 1 m² per year = Rs. 5000
Rent of 1 m² per month = Rs. 5000
/12
Rent of 1 m² for 3 months=Rs.3×5000
/12
Rent of 1320 m² for 3 months=Rs. ( 3×5000×1320
/12)
= Rs.16,500,000
hope it helps !
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