Question

2. The units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself​

Answer 1

Answer:

The unit digit of a two-digit number is 3

u = 3

and seven times the sum of the digits is the number itself.

7(t+u) = 10t+u

Substitute 3 for u:

7(t+3) = 10t+3

7t+21 = 10t+3

-3t = -18

t = 6

The tens digit is 6 and the units digit is 3, so the number is 63.

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Answer 2

Answer:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.