Question

2. The value of 'C' for which the pair of equations Cx - y = 1 and 6x - 2y = 2 will have unique
solution is:
a) c is not equal to 3
b) c is not equal to 2
c) c = 3
d) no value
​

Answer 1

Answer:

1

Secondary School Math 5 points

Find the values of 'c' for which the pair of equation cx-y=2 and 6x-2y=3 will have infinitely many sloution

Ask for details Follow Report by Khushikudi 23.03.2018

Sakshi15403

value of c is 3

The question is wrong ...for infinitely many sol. We have evrything equal ... But here 2/3 is not equal to 1/2

Sakshi15403

ok

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Answers

dharun1

dharun1 Ace

For infinitely many solutions the following situation is there in two lines

a1/a2=b1/b2 = c1/c2

a1=c,a2=6,b1=-1,b2=-2,c1=-2,c2=-3

c/6=-1/-2 = -2/-3

therefore c=3 also c=4

hope this would be clear to you

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pinquancaro Virtuoso

Answer:

For no value of c the pair of equations will have infinitely many solutions.

Step-by-step explanation:

Given : The pair of equation cx-y=2 and 6x-2y=3 will have infinitely many solution.

To find : The value of 'c'?

Solution :

Condition for infinitely many solutions is

\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}

Given lines are cx-y=2 and 6x-2y=3

So, a_1=c,b_1=-1,c_1=-2,a_2=6,b_2=-2,c_2=-3

Substitute in the condition,

\frac{c}{6}=\frac{-1}{-2}=\frac{-2}{-3}

\frac{c}{6}=\frac{1}{2}=\frac{2}{3}

Take first two,

\frac{c}{6}=\frac{1}{2}

Solve,

c=3

Take first and last,

\frac{c}{6}=\frac{2}{3}

Solve,

c=4

Since, c has different values.

Hence, For no value of c the pair of equations will have infinitely many solutions.