2. The value of k for which x – 1 is a factor of p(x) = 2
2 + kx +√2
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Step-by-step explanation:
If x-1 is a factor of 2+kx+ root 2 then it will be equal to 0
X-1 =0
X = 1
Put this vale in p(1) = 2 + k(1) +root 2
= k = - ( 2+root 2)
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