Question

2)The velocity time graph for a cycle is shown in the below figure.

Find: i) velocity of the cycle at point C

ii)Acceleration acting on the cycle between A and B

iii)Acceleration acting on the cycle between B and C

iv) Displacement of the body from B to D

Answer 1

Given.: The velocity time graph for a cycle

To find : i) velocity of the cycle at point C

ii)Acceleration acting on the cycle between A and B

iii)Acceleration acting on the cycle between B and C

iv) Displacement of the body from B to D

Solution

Velocity of cycle at point C = 40 km/hr

Acceleration acting on the cycle between A and B

acceleration = dv/dt

=(40-20)/(3-0)

= 20/3

= 6.67 km/hr

iii)Acceleration acting on the cycle between B and C

= (40 -40)/÷6-3)

= 0

Displacement of the body from B to D

area under graph from B to D

= (1/2)(3 + 5) × 40

= 160 km

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