Question

2. The velocity-time (v-t) graph for a particle in straigh
line motion is given below.
The corresponding acceleration-time (a-t) graph
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Answer 1

Explanation:

at t=0 S = -10m and V= 0

For acceleration time graph

a=dV/dt

or it may called as slope of v-t curve

hence plot the a-t curve

for first 2 sec

velocity is increasing constantly

slope is 10/2 = 5m/s^2 =a for first 2 sec

then for time t=2 to t= 4 velocity is constant hence no change in velocity slope is zero hence acceleration is zero

for next time t=4 to t= 8 velocity decreases linearly from 10 to -10 hence slope is -20/4 is -5m/s^2 = a (acceleration)

fot time t=8 to t=10 velocity increase from -10 to 0

slope is 10/2 = 5m/s^2