Question

2.
The vertices of a triangle ABC, right angled at B, are A (-2, 1), B(2,-2) and C(K, 2). Find the
value of K
1M​

Answer 1

Step-by-step explanation:

Area = (1/2)[x1(y2-y3)+x2(y3–y1)+x3(y1-y2] = (1/2)[-2(-3–4)+2(4–1)+5(1+3)]=20 s.u. We’ve taken A to be (-2,1), B:(2,-3) & C:(5,4).

Now determine the length BC = [((5–2)²+(4+3)²]^(1/2)=√(58). Altitude thru’ A = 2A/BC = 2 x 20/√58 = 40/√58

Answer 2

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