2. The wavelength of a spectral line emitted
by hydrogen atom in the Lyman series is
16/15R cm. What is the value of n,?
(R = Rydberg constant) (E-2007)
1 2 2 3 3 4 4 1
Answers
Answered by
2
Answer:
121.6
nm
Step-by-step explanation:
Explanation:
1
λ
=
R
(
1
(
n
1
)
2
−
1
(
n
2
)
2
)
⋅
Z
2
where,
R = Rydbergs constant (Also written is R
H
)
Z = atomic number
Since the question is asking for
1
s
t line of Lyman series therefore
n
1
=
1
n
2
=
2
since the electron is de-exited from 1
(
st
) exited state (i.e n
=
2
) to groundstate(i.e n
=
1
) for first line of Lyman series
Therefore plugging in the values
1
λ
=
R
(
1
(
1
)
2
−
1(
2
)
2
)
⋅
1
2 Since the atomic number of Hydrogen is 1. By doing the math, we get the wavelength as λ
=
4
3
⋅
912
.
A
since 1
R
=
912
.
A
therefore λ
=
1216
.
A or
r
λ
=
121.6
nm
Answered by
28
Answer: n = 4
it's simple friend
for Lyman's series n1 = 1
1 / wavelength = R [ 1 / n1² — 1 / n2² ]....... formula
15R./ 16 = R [ 1— 1 / n2²]
16n² — 16 =15n²
n² =16
n = 4
plz mark it as a brainlist
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