Question

2) The width of a rectangle
is bem, less than its length
and its perimeter is 0.467.
find its area in square mm.
I want the answer with solving steps and diagram

Answer 1

Step-by-step explanation:

Let the length of old rectangle = l

Let the breadth of old rectangle = b

Perimeter of the old rectangle = 2(length + breadth) = 2(l + b)

When the length and the breadth of the rectangle are doubled, then

length of the new rectangle = 2l

breadth of the new rectangle = 2b

∴ Perimeter of new rectangle = 2(length + breadth)

= 2(2l + 2b)

= 2 × 2(l + b)

= 2 × perimeter of the old rectangle [∵ perimeter of old rectangle = 2(l + b)]

Hence, the perimeter of the new rectangle will become two times of the perimeter of the old rectangle.