Question

2.
The zeroes of the polynomial x² - 3x - m (m + 3) are
(a) m, m + 3
(b) -m, m + 3 (c) m, -(m + 3)
(d) -m, -m+3)​

Answer 1

Step-by-step explanation:

x^2 - 3x - m(m+3) = 0

x^2 - 3x = m(m+3)

x^2 - 3x = m(m + 3)

Now , x = 0 ,

m(m+3) = 0.

So, either m or (m + 3) should be equal to zero.

Ans: (A)