Question

2.
The zeroes of the polynomial x2 - 3x-m (m + 3) are
(a) m, m + 3 (b) m,m + 3 (c) m, (m+3)
(d) m (m+3)​

Answer 1

Answer:

Given: equation x

2

−3x−m(m+3)=0, where m is a constant

To find the roots of the equation

Sol: the given equation is of form ax

2

+bx+c=0∴a=1,b=−3,c=−m(m+3)

We know the roots of the equation can be find out using the formula,

x=

2a

−b±

b

2

−4ac

Substituting the values of a, b, c, we get

x=

2

−(−3)±

(−3)

2

−4(1)(−m(m+3)

⟹x=

2

3±

9+4m

2

+12m

⟹x=

2

3±(2m+3)

or x=

2

3+(2m+3)

,x=

2

3−(2m+3)

⟹x=m+3,x=−m are the required roots of the equation.