2. There are 8 sections of ninth class in a school The number of students in them is 56, 46, 65, 53, 60, 64, 59 and 61 respectively. Find A.M. of the number of these sections.
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Answer:
A.M of each section = Total number students of all sections/ number of sections
Then A.M = (56+46+65+53+60+64+59+61)/8
= 464/8
=58
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