Question

2. There are three natural numbers. The first and
second are less than the third by 40% and 50%
respectively. What percentage of the second
number is the first number?
(A) 125%
(B) 133/3%
(C) 1162/3%
(D) 120%​

Answer 1

Answer:

120 %

Step-by-step explanation:

let the third number be 100

hence we have

1st number - 40% less than 100 = 60

2nd number - 50% less than 100 = 50

As per question we have to find how much percentage of the 2nd number is present inside the 1st number which can be found by dividing

1st number by 2nd number × 100

(number for which we have to find result/ number being compared to × 100)

= 60/50 × 100

= 120%

Answer 2

The answer is (D) 120%.

Let's call the third natural number "x". If the first number is less than the third by 40%, then the first number is

x - (0.40 * x) = x - 0.40x = 0.60x.

Similarly, if the second number is less than the third by 50%, then the second number is

x - (0.50 * x) = x - 0.50x = 0.50x.

Now we want to find what percentage of the second number is the first number. To do this, we can divide the first number by the second number and multiply by 100 to get a percentage:

(0.60x) / (0.50x) * 100% = 1.2 * 100% = 120%

So, if the first number is less than the third by 40% and the second number is less than the third by 50%, then the first number is 120% of the second number.

For more such questions on percentage: https://brainly.in/question/21072430

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