Question

2.
Three numbers are in the ratio 2: 3:4. The sum of their cubes is 33957. Find thi
numbers.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let the three numbers be 2x, 3x, 4x.... and let x be a positive integer....

According to the Question,

${(2x)}^{3} + (3x)^3 + (4x)^3 = 33957 \\ \\ = > 8x^3 + 27x^3 + 64x^3 = 33957 \\ \\ = > 99x^3 = 33957$

$x^3 = \frac{33957}{99} \\ \\ = > x^3 = 343 \\ \\ = > x = \sqrt[3]{343} \\ \\ = > x = 7$

Therefore, the three numbers are,

$2x = 2(7) = 14 \\ 3x = 3(7) = 21 \\ 4x = 4(7) = 28$

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