Question

2. Thrice a number when decreased by one-fourth of a
give
3. The sum of three consecutive multiples of 3 is 72. Find the numbe
4. Half of a number is 45 less than the number. Find the number.​

Answer 1

Answer:

Let the number be x.

twice =2x

When it is decreased by 7 we get the following equation:

2x−7=45

⇒2x=45+7

⇒2x=52

⇒x=252​

∴x=26

The number is 26.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Let the first no. be x

Second no. be x+3

Third no. be x+6

So according to question

x+x+3+x+6=72

3x+9=72

3x=72-9

3x=63

x=63/3

x=21

So the no. are

x=21

x+3=21+3=24

x+6=21+6=27