Question

√2 times the distance between (0,5)and (0,-5)​

Answer 1

Answer:

10√2 unit.

Step-by-step explanation:

√2 times the required distance.

= √2×√(0-0)^2+(-5-5)^2

=10√2

Answer 2

10√2 is √2 times the distance between (0,5)and (0,-5)​

Step-by-step explanation:

Given data

• Co-ordinate of two point are given below

         $\mathbf{(x_{1},y_{1})=(0,5)}$

         $\mathbf{(x_{2},y_{2})=(0,-5)}$

• We know distance formula between two co-ordinate, which are given below

        $\mathbf{D=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}}$

• On putting respective value in above equation

        $\mathbf{D=\sqrt{(0-0)^{2}+(-5-5)^{2}}}$

        $\mathbf{D=\sqrt{(-10)^{2}}}$

         D = 10

• Now come to question distance is √2 times the distance between (0,5)and (0,-5)​

        Means

        Distance = √2 × D

        Distance = √2 × 10

       Distance = 10 ×√2 = This is the answer.