Question

2)
To solve x + y = 3: 3x - 2y - 4 = 0 by determinant method find D.
a.5 6.1 c. - 5 d. - 1​

Answer 1

Answer:

-5

Step-by-step explanation:

x+y=3---------- eq 1

3x-2y=4-------eq 2

Comparing eq 1 and 2 with ax+by=c

a1= 1,b1=1,c1=3

a2=3,b2=-2,c2=4

D=

$|a1 \: b1 \\ a2 \: \: b2 ||$

$|1 \: \: \: \: \: \: \: \: 1 \\ 3 \: \: \: - 2 | \:$

= 1×(-2) - 1×3

=-2 -3

= -5

Therefore the value of D is -5