Question

2 to the power - log 7 to the base 1/2​

Answer 1

Answer:

7

Step-by-step explanation:

Mark me as brainliest

Answer 2

ANSWER:

$\purple{ \to}\red{ \tt{ {2}^{ log_{ \frac{1}{2} }(7) } }}$

We know that

$\small{ \sf{ \implies \green{ \dfrac{1}{2} } \red \to \purple{ {2}^{ - 1} } }}$

Substituting we get

${\rm{ \red{ \to}{ {2}^{ log_{ {2}^{ - 1} }(7) } } }}$

Using

${ \rm{\implies \green{ \log_{ {b}^{x} }( a) } \red{ \to } \purple{\frac{1}{x} \log_{b}(a) } }}$

$\orange\to{ \rm{ {2}^{ - log_{2}(7) } }}$

Using

$\implies \green{ - \log_{x}(a) } \red \to \purple { \log_{x}( \frac{1}{a} ) }$

We get

$\blue \to{ { \rm{ {2}^{ log_{2}( \frac{1}{7} ) } }}}$

Using

$\implies \green{ {x}^{ \log_{x}(a) } }\red{ \to} \purple{a}$

${ \bf{ \green \to \dfrac{1}{7} }}$

Hence,

${\bf{ \purple{{2}^{ log_{ \frac{1}{2} }(7) }} \longrightarrow \orange{ \dfrac{1}{7} } }}$