Question

2 to the power m - 2 to the power n = 56
i.e. 2^m-2^n=56
find the value of m and n

Answer 1

2^m -2^n = 56

m must be more than n for equation to hold

2^m -2^n =8*7

[2^(m-n) - 1](2^n)= 8*7

You get case of n=3 this way

Like wise you can go for 14*4,56*1,28*2 combinations.

n=0,1,2,3 with m= LOG BASED VALUESin all cases except the above.

Answer 2

$✅❤️Answer❤️$

2^m -2^n = 56

m must be more than n for equation to hold

2^m -2^n =8*7

[2^(m-n) - 1](2^n)= 8*7

You get case of n=3 this way

Like wise you can go for 14*4,56*1,28*2 combinations.

n=0,1,2,3 with m= LOG BASED VALUESin all cases except the above.