Question

2 train tickets from city s and b as well as 3 tickets from city s to c cost 77 but 3 tickets from city s to b as well as 2 tickets from city s to c cost rs 73 what have been fares from cities b as well as c from s

Answer 1

Let the fare from city s to b be Rs. x and from city s to c be Rs. y
Given that, 2 train tickets from city s to b and 3 tickets from city s to c cost Rs. 77.
i-e, 2x + 3y = 77  .......... (1)
Also given that, 3 tickets from city s to b and 2 tickets from city s to c cost Rs. 73.
i-e, 3x + 2y = 73  ........... (2)
Now we solve both the equations to get the values of x and y.
For this, first multiply equation (1) by 3 and equation (2) by 2.
Eq. (1)   ⇒    6x + 9y = 231  ........ (3)
Eq. (2)   ⇒    6x + 4y = 146  ........ (4)
Now subtracting above equations, we get:
(6x + 9y) - (6x + 4y) = 231 - 146
6x + 9y - 6x - 4y = 85
5y = 85
y = 85 / 5
y = 17
Now put this value of y in equation (1):
2x + 3y = 77
2x + 3 (17) = 77
2x + 51 = 77
2x = 77 - 51
2x = 26
x = 26 / 2
x = 13
Thus fare from city s to b is Rs. 13 and fare from city s to c is Rs. 17.
Hope it will help you. Thanks.

Answer 2

Let the fare of train from city s to b be ₹ X & from city s to c be ₹ Y

2X + 3Y = 77 -----------( 1)
3X + 2Y = 73 -----------( 2)

multiply eq(1) by 3 & multiply eq(2) by 2



6X + 9Y = 231 ----------( 3)
6X + 4Y = 146 -----------(4)

Subtract eq( 4) from eq (3)

6X + 9Y = 231
6X + 4Y = 146
(-) (-) (-)
-----------------------
5y = 85


y = 85/5
y = 17.

Put the value of y in 1 or 2

2X + 3(17) = 77


2X + 51 = 77

2X = 77 - 51 = 26.

2X = 26

X = 26/2 = 13

X = 13 and Y = 17

Hence, the fare from city s to b is ₹13 & fare from city s to c is ₹17

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Hope this will help you.....