Question

2 trains are moving in opposite direction at the rate 60km/hr and 90km/hr. Their lengths are 1.10km and 0.9km respectively. What is the time taken by the slower train to cross the faster train in seconds?

Answer 1

Relative speed = (60+90) km / hr =

↬150 km / hr = 150 × $\frac{15}{8}$

↬m / sec =

↬$\frac{125}{3}$ m / sec

Distance covered by the slower train to cross the faster train

= (1.1+0.9) km = 2 km = 2000 m

The time taken by the slower train to cross the faster train in second

= $\frac{Distance}{Speed}$

2000/125/3 = 16 × 3 = 48 Seconds

Answer 2

$\pink{ \underline{ \blue{ \boxed{48}}}}$

Solution:

Distance = 1.1 + 0.9 = 2km.

Speed = ( 60 + 90 ) = 150.

$\sf time \: taken = \frac{2 \times 1000}{150 \times \frac{5}{18} } = { \blue{ \underbrace{ \underline{ \overline{ \boxed{ \sf 48 \: seconds}}}}}}$