2 transistor cost rs:480,they are sold at a profit of 19% other at a loss of 15%.if the selling price are equal. Find the cost pf lower priced one
Answers
Let the selling price be x:
Cost price of the first one:
Cost Price = Selling Price + Profit
Cost Price = 100 + 19 = 119%
119% = x
100% = (x/119) x 100 = 100/119 x
Cost price of the second one:
Cost Price = Selling Price - Loss
Cost Price = 100 - 15 = 85%
85% = x
100% = (x/85) x 100 = 20/17 x
Find the selling price of 1 transistor:
The total cost price is Rs 480
100/119 x + 20/17 x = Rs 480
240/119x = 480
x = 480 ÷ 240/119
x = Rs 238
Find the cost price of the first transistor:
Cost Price = 100/119 x = 100/119 x 238 = Rs 200
Find the cost price of the second transistor:
Cost Price = 20/17 x = 20/17 x 238 = Rs 280
Answer: The cost of the lower priced one is Rs 200
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SHORTCUT:
Cost Price of the first one =1/1.19 x 480 ÷ (1/1.19 + 1/0.85) = Rs 200
Cost Price of the second one =1/0.85 x 480 ÷ (1/1.19 + 1/0.85) = Rs 280
Therefore the cheaper one is Rs200
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