Question

2. Two charged particles are at a distance 1mm apart. Find the minimum coulomb force between
them​

Answer 1

$\huge \sf \fcolorbox{red}{pink}{Solution :)}$

Let us assume that , the magnitude of two charged particles be Q1 and Q2

Given , the distance between two charged particles (r) is 1 mm or 0.001 m

We know that , the force between two charges is given by

$F = \frac{k (Q_{1} \times Q_{2} )}{ {(r)}^{2} }$

Here , k is a coulomb's constant which is equal to 9 × 10^9

$\sf \mapsto F = \frac{9 \times {(10)}^{9} }{ {(0.001)}^{2} } (Q_{1} Q_{2} ) \\ \\ \sf \mapsto F = 9 \times {(10)}^{9} \times {(10)}^{ - 6} (Q_{1} Q_{2} ) \\ \\ \sf \mapsto F = 9 \times {(10)}^{3} (Q_{1} Q_{2} ) \: \: Newton$

Hence , the force between two charged particles is 9 × (10)³ × (Q1 × Q2) Newton

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