Question

2. Two charges separated by a distance of
r. If the static electric force is 3.6 N, what is
the distance between both charges (1 °C =
10-6 C and k = 9.109 N.m2.c-2)
9ЫС​

Answer 1

$\large\underline{\bigstar \: \: {\sf Correct \; Question-}}$

Two Charges separated by a Distance of r. If the static electric force is 3.6N , what is the distance between both the charges (1μC = ${\sf 10^{-6}C}$ and K = ${\sf 9\times 10^9\: Nm^2/C^2}$

$\large\underline{\bigstar \: \: {\sf Given-}}$

• Two Charges ${\sf Q_1=10^{-6}C\: and Q_2=10^{-6}C}$
• Static Electric force between both charges (F) = 3.6N

$\large\underline{\bigstar \: \: {\sf To \: Find -}}$

• Distance between both charges (r)

$\large\underline{\bigstar \: \: {\sf Formula \: Used -}}$

$\bullet\underline{\boxed{\sf F=9\times 10^9 \times \dfrac{Q_1Q_2}{r^2}}}$

$\large\underline{\bigstar \: \: {\sf Solution-}}$

$\implies{\sf 3.6 = 9\times 10^9\times \dfrac{10^{-6} \times 10^{-6}}{r^2} }$

$\implies{\sf r^2=\dfrac{9\times 10^9\times 10^{-12}}{3.6} }$

$\implies{\sf r^2=2.5\times 10^{-3}}$

$\implies{\sf r^2=25\times 10^{-4}}$

$\implies{\bf r=5\times 10^{-2}\:m }$

$\large\underline{\bigstar \: \: {\sf Answer-}}$

Distance between both charges is ${\bf 5 \times 10^{-2}\:m}$