Question

2.Two chords are equidistant from centre if length of one chord is 12 cm then find the length of
other chord.

Answer 1

Answer:

a circle, the perpendicular bisector from the centre to the mid point of the

chord, forms a right angled triangle as shown in the figure.

Now,

=>OA

2

=OM

2

+MA

2

=>OA

2

=8

2

+6

2

(Since,

MA is half of the chord AB )

=>OA=Radius=10cm

Let the other chord be PQ.

Similarly,

=>OP

2

=ON

2

+NP

2

=>10

2

=6

2

+NP

2

(Since, NP is half of the chord PQ )

=>NP=8cm

SO, PQ=2×NP=16cm

Answer 2

Answer:

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Step-by-step explanation:

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m,lnjkl;,.mnkl;

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nkl, mnjkmlkl,mkl

Answer =16