Question

2. Two classmates Salma and Anil simplified two different expressionsduring the revision
hour and explained to each other their simplifications. Salma explains simplification of
V2 / (V5 +73) and Anil explains simplification of 728 + 798 +v147. Write both
simplifications. What value does it depict.​

Answer 1

Answer:

34

Step-by-step explanation:

because because at the simplification first of all Z2 and then just write a bracket and write v5 plus 73 then bracket then what will happen that 1605 simplification should be it to another bracket it should be the best they value doesn't it so it's easy to adjust write the multiplication of that then divide that what will be the smallest reduce number then reduced number by the division of the substraction then your answer will be there and now it's a long method but you should that is set up so now the answer comes in 34

Answer 2

Two classmates Salma and Anil simplified two different expressions during the revision hour and explained to each other their simplifications. Salma explains simplification of √ 2/√5 +√3 by rationalizing the denominator and Anil explains simplifications of (√2 + √3)(√2 − √3) by using the identity (a + b)(a − b). Answer the following question.

Question (1) :- 1. What is the conjugate of √5 + √3.

a) √5 + √3

b) √5 − √3

c) √5 × √3

d) √5/√3

Answer :-

we know that, to find the conjugate of binomial surds, we changes the sign in between the terms, that is,

• '+' becomes '-' .
• '-' becomes '+'.

therefore, the conjugate of √5 + √3 is √5 - √3 . (Option b) .

Question (2) :- By rationalizing the denominator of √ 2/√5 +√3

Salma got the answer:

a) √ 2/√5 −√3

b) √ 2(√5 −√3)/2

c) √5 − √3

d) √ 2(√5 +√3)/2

Solution :-

→ √2/(√5 + √3)

rationalizing the denominator we get,

→ {√2/(√5 + √3)} * {(√5 - √3)/(√5 - √3)}

→ {√2 * (√5 - √3)} / {(√5 + √3) * (√5 - √3)}

using (a + b)(a - b) = a² - b² in denominator now,

→ {√2 * (√5 - √3)} /{(√5)² - (√3)²}

→ {√2 * (√5 - √3)} / (5 - 3)

→ {√2 * (√5 - √3)} / 2

→ √2(√5 - √3)/2 (Option b)

Question (3) :- Anil applied _______ identity to solve (√5 + √7)(√5 − √7)

a) (a + b) (a + b)

b) (a + b) (a − b)

c) (a − b) (a − b)

d) a^2+2ab+b^2

Solution :-

→ (√5 + √7)(√5 − √7)

Let ,

√5 = a

√7 = b

then,

→ (√5 + √7)(√5 − √7) = (a + b)(a - b) (Option b) .

Question (4) :- (√2 + √3)(√2 − √3) =________

a) −1

b) 1

c) 5

d) -5

Solution :-

using (a + b)(a - b) = a² - b² we get,

→ (√2)² - (√3)²

→ 2 - 3

→ (-1) (Option a) .

Question (5) :- Addition of two irrational numbers is equal to _______.

a) Rational

b) Irrational

c) Integers

d) Whole Number

Solution :-

Addition of two irrational numbers is equal to Irrational number . (Option b).

Note :- if the irrational parts of the numbers have a zero sum (cancel each other out), the sum will be rational.