Question

2 Two cross roads, each of width 5 m, run at right angles through the centre
of a rectangular park of length 70 m and breadth 45 m and parallel to its
sides. Find the area of the roads. Also find the cost of constructing the
roads at the rate of 105 per m².​

Answer 1

$hello \: mate$

Question :- 2 Two cross roads, each of width 5 m, run at right angles through the centre of a rectangular park of length 70 m and breadth 45 m and parallel to its sides. Find the area of the roads. Also find the cost of constructing the roads at the rate of 105 per m².

Answer :- Rs. 57750.

Step by step explanation :

Let ABCD be the rectangular park then EFGH and IJKL are the two rectangular roads with width 5m.

Given that length of rectangular park

= 70m Breadth of rectangular park

= 45m Area of the rectangular park

= Length x Breadth

= 70 m x 45 m

= 3150 m2

Area of the road EFGH

Area of the road EFGH = 70 m x 5 m = 350 m²

Now, Area of the road JKIL

Now, Area of the road JKIL = 45 m x 5 m = 225 m²

From the figure, it is clear that area of MNOP is common to the two roads.

Thus, Area of MNOP

= 5 m x 5 m = 25 m²

Therefore, Area of the roads

= Area of EFGH + Area of JKIL – Area of MNOP

= (350 + 225) m²– 25 m²

= 550 m²

Again, it is given that the cost of constructing the roads = Rs. 105 per m²

Therefore, Cost of constructing 550 m2 area of the roads = Rs. (105 x 550)

= Rs. 57750.

I hope my answer helps you.