2. Two elements X and Y have atomic weights of 14 and
16. They form a series of compounds A, B, C, D and E
in which the same amount of element X, Y is present in
the ratio 1 : 2:3: 4: 5. If the compound A has 28 parts
by weight of X and 16 parts by weight of Y, then the
compound of C will have 28 parts weight of X and
(a) 32 parts by weight of Y
(b) 48 parts by weight of Y
(C) 64 parts by weight of Y
(d) 80 parts by weight of Y
Answers
Answer:
It's too simple dear...
Explanation:
Answer is (a) 32 parts...
Need explanation...?
I suggest to read law of multiple proportion by mass...
It's better way of learning to learn concepts first and then apply in questions.... Please use ASKIITIANS app for better learning...
Also you can use TOPPER LEARNING APP....
.. Sorry for compound b it will be 32... For c it will be 48...I didn't see it...
Well tum mere answer ki khichdi bna rhi ho... Majak kr rha hun...
Let's see how it is...
Need to explain....?
Dear actually I have to go coaching.... Can I explain later.... Wait till night.... Askiitians pe jao to ek bar......
Dekho...
For equal mass of x all compound a, b, c, d, e contains y in different amounts... But there ratio is given...
1:2:3:4:5...so for 1 part of x in compound a there will be 1 part of y in a... 2 part of y in b... 3 part of y in c... and so on....
So for 32 parts of x in a don't you think if 16 part of y is in a then it will be 32 in b... 48 in c... 64 in d... And so on...
Actually I am JEE ADVANCED ASPIRANT... You can ask any question from me..... Good bye...
Your class?... Your class...? 9th or 11th... So why you are asking so simple questions... You have studied it in 11 th... Good bye...
Answer:
b)48 parts by weight of y
Explanation:
refer attachment
