Question

`2. Two Express trains A and B start from two stations 250 km apart Irom eachother with an initial velocity of 72 km/h and 90 km/h respectively After 1.5 hours,due to some inconvenience, both the trains start running on the sante traetowards each other. A farmer passing by, watches both the trains comintowards each other and stand on the track and raises his vred shirt. Both trainsdecelerate uniformly by 0.5 m/s2 and finally stop and the mishap is inverted.Read the passage carefully and answer the questions.(iii)What values are promoted by the farmer,`

Answer 1

Answer:

bleave me this will get you to your answer https://www.studyisle.co.in/details/motion

this is my answer for you Explanation:

Given Train starts at the same time.

Hence, Time remains constant.

Speed of Train 'T1' be 'S1' = 40 km\hr

Speed of Train 'T2' be 'S2' = 45 km\hr

Let X be the distance at which trains meet.

Train T2 travels X+40 km more than Train T1

According to the formula.

Speed=

Time

Distance

Time=

45

X+40

Time=

40

X

From above two equations.

40

X

=

45

X+40

45×X=40×X+40×40

5×X=1600

=320 km

Distance between two Stations = Distance at which train T1 meet + Distance at which Train T2 meet + Distance train T2 travels

= 320+320+40

= 680