Question

2. Two forces 10N along x-axis (horizontal) and 14N along y-axis (vertical) are acting
perpendicularly (angle between forces is 90°) upon a body. What can be the magnitude of resultance force and the direction ​

Answer 1

Answer:

R =√244

α= tan ^-1 (5/7)

Explanation:

R^2 = 10^2+ 14^2

R=√244

tan α=10/14

α= tan ^-1 (5/7)

Answer 2

Given

• Force on the x axis = 10 N
• Force on the y axis = 14 N
• Angle between the two forces = 90°

To Find

• Magnitude of the resultant force and the direction

Solution

● R = √Rx² + Ry² [Because the angle is 90° and cos 90° = 0]

● tanβ = Bsinθ/(A+Bcosθ)

✭ Resultant of the forces :

→ R = √Rx² + Ry²

→ R = √{10² + 14²}

→ R = √{100+196}

→ R = √296

→ R = 17.2 N

✭ Direction of the force :

→ tanβ = Bsinθ/(A+Bcosθ)

→ tanβ = Bsin90°/(A+Bcos90°)

• A = 10N
• B = 14N

→ tanβ = 14(1)/(10+0)

→ tanβ = 14/10

→ tanβ = 1.4

→ β = tan‾¹(1.4)

→ β = 54.46°