Question

2 Two hemispheres of the same diameter as that of a cylinder are attached to the ends of a cylinder of diameter 7 cm and
height 10 cm. Find the surface area of the solid.
ns1. 374 sq cm
X 2 594 sq cm
X 3. 1056 sq cm
X 4. 836 sq cm​

Answer 1

Step-by-step explanation:

2πrh + 4πr²

2πr (h+2r)

2× 22/7× 7/2(10+2× 7/2)

22×17

= 374 cm²

Answer 2

Answer:

374cm²

Step-by-step explanation:

Given,

• diameter of the cylinder :- 7cm
• height of the cylinder :- 10cm
• diameter of the hemisphere :- 7cm

We know,

• radius,r = d/2 = 7/2 = 3.5cm
• curved surface area of a cylinder :- 2πrh
• surface area of a hemisphere :- 2πr²
• S.A. of two hemispheres :- 4πr²

Solution :-

• area of the solid = area of cylinder + area of two hemispheres
• area = 2πrh + 4πr²
• area = 2πr(h+2r)
• area = 2x3.14x3.5(10+2x3.5)
• area = 2x3.14x3.5(10+7)
• area = 2x3.14x3.5(17)
• area = 373.66cm²

Approximately 374cm²

Hence,

• Area of the solid = 374sq cm

Hope it helps