Physics, asked by telukunthlaanil, 7 days ago

2. Two masses m, = 5 kg and m, = 4,8 kg tied to a string are hanging over a light frictionless pulley, m = The acceleration of the masses when left free to move is (g = 9.8 ms ia a) 4.8 ms 2 b) 9.8 ms 2 c) 5 ms 2 d) 0.2 ms 2.










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Answers

Answered by manikandanmanik07
1

Answer:

Explanation:

x be downwards

y be upwards

x(g)-t=x

t-y(g)=y

a=x-y/x+y(g)

5-4.8=0.2

so,

0.2/9.8*9.8+0.2m/s^2 opt d hope it helps

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Answered by AnanyaBaalveer
0

Answer:

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