2. Two masses m, = 5 kg and m, = 4,8 kg tied to a string are hanging over a light frictionless pulley, m = The acceleration of the masses when left free to move is (g = 9.8 ms ia a) 4.8 ms 2 b) 9.8 ms 2 c) 5 ms 2 d) 0.2 ms 2.
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Answer:
Explanation:
x be downwards
y be upwards
x(g)-t=x
t-y(g)=y
a=x-y/x+y(g)
5-4.8=0.2
so,
0.2/9.8*9.8+0.2m/s^2 opt d hope it helps
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Answer:
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